**The plate with a hole ! Who didn’t start to learn FEA by this simple example ?**

I remember when i modeled for the first time this plate on the first NASTRAN in DOS during my FEM course, what a memorable moment… i had to run the program like a hundred times before getting a correct model… thanks to modern GUI, we can now focus on the real problem which is not the modelling, but the understand of how to get the accurate theoretical results and which parameters are important for that.

Meshes are the base of Finite Element Analysis and i will demonstrate you why !

First the problem formulation:

So, as the title indicate, this is a simple plate of **dimensions L=100 mm x h = 50 mm** made with steel with a hole of **radius r = 20 mm** in the middle.

As we will perform a simple linear static analysis, only 2 coefficients are required to define the material properties, the Young’s Modulus **E = 210000 MPa** and the poisson’s ration **ν = 0.3**.

a pressure load F = 100N/mm2 is applied on the 2 sides of the plate.

The first thing to do is to change and adapt the problem for FEA analysis:

**Why do I have to formulate again the problem for FEA ?**

– if you look at the previous problem, you will notice that there is no boundary condition, so the plate isn’t fixed in space. it introduce a degree of freedom that is not wanted in FEA Analysis and will complicate everything.

– When possible, symmetries should always be considered in the model in order to reduce the number of elements in the analysis. Moreover, these symmetry conditions will play the role of boundary conditions in this analysis.

In FEA analysis, the number of mesh elements and mesh element size is very important because accuracy of the results depend on it.

Even if you can calculate very complex problems of mechanics with FEA which are approaching real world models, FEA is still a numerical approximation method. So more elements you have, the smaller they are and more the results will be accurate.

here is the simple analysis process to solve this problem:

1. Create Material with properties defined above ( **E = 210000 MPa** and **ν = 0.3 **)

2. Create a 2D property of plate (Thickness = 1 mm)

3. Create the plate model using geometrical tools.

4. Mesh the plate with finite elements (choice of element size, element order and element type is critical)

5. Assign the symmetry boundary conditions to the 2 symmetrical edges of the plate.

6. Assign the Pressure load of 100N/mm2 to the right edge of the plate

7. Create a linear static analysis case

8. Launch the Analysis

9. Use the post process tools to obtain the displacement and von mises stress results

Here is a video tutorial to explain the process with more details:

In order to see the influence of the Mesh size, it is interesting to create several models of the plate with different mesh sizes to compare the results at a same specific node.

Here is the results you will get

You can observe that the Von Mises Stress results are strongly correlated with the mesh size, but this is not the only factor.

The Type of Mesh has also a very big influence on the speed of convergence.

– Simple triangular elements with 3 nodes TRI3 will almost always give unaccurate results, at least the mesh size is very coarse.

– High level triangular elements with 6 nodes TRI6 will give much better results than TRI3, because they have a middle node on each edge. the only disadvantage is that the number of nodes in the model is much higher and solver will take more time and memory space for the calculation.

-Simple quad elements are better than simple triangular elements because they have 4 nodes instead of 3, but meshing with quad element may not be appropriate for all types of geometries.

Here is a comparison graph between TRI3 and TRI6 elements to compare the convergence speed:

Let me a comment to know more about the subject !

see you next week for another interesting FEA subject :)

Krzysztof says

The problem is that a beginner even if knows about that correlation don’t have a clue how big shuld a mesh element be.

Leonid says

Hi guys,

AS i know, for 2D elements is not correct to use the elements size smaller than plate thickness.